MathsLearner
New member
- Joined
- Aug 13, 2017
- Messages
- 27
I am trying to solve the below problem
My attempt is i am considering the other axis as z, not sure why it was not mentioned. Considering the right triangle 3,4, the area of the right triangle is
[MATH]\frac 1 2 yz[/MATH]. I need the equation of y and z in terms of x, and the x coordinates vary from 0 to 5. The equation of line1 is [MATH]y=-\frac 4 5 x + 4 [/MATH]The equation of line 2 is [MATH]z=-\frac 5 3 x + 3 [/MATH]. Hence the volume is [MATH] V = \int_0^5 \frac 1 2 (-\frac 4 5 x + 4)(-\frac 5 3 x + 3) [/MATH]. But the answer is not matching. What is the mistake? Please help.
My attempt is i am considering the other axis as z, not sure why it was not mentioned. Considering the right triangle 3,4, the area of the right triangle is
[MATH]\frac 1 2 yz[/MATH]. I need the equation of y and z in terms of x, and the x coordinates vary from 0 to 5. The equation of line1 is [MATH]y=-\frac 4 5 x + 4 [/MATH]The equation of line 2 is [MATH]z=-\frac 5 3 x + 3 [/MATH]. Hence the volume is [MATH] V = \int_0^5 \frac 1 2 (-\frac 4 5 x + 4)(-\frac 5 3 x + 3) [/MATH]. But the answer is not matching. What is the mistake? Please help.