Lime said:
I don't get the whole "with respect to" thing.
As an example, what would dy with respect to dx mean? I know it's written as dy/dx.
If you have some function y=f(x), by writing
dxdy=...
You should be asking yourself "as x changes, what is happening to y?" and when you solve for
dxdy you are calculating just that. The instantaneous change in y when x changes.
So, given y=2x, you calculate dy/dx to be 2. Thus when x changes by any amount, y will change twice as much (or fast if y is a function of time)!
Alternatively, it may be necessary/helpful to consider
dydx. Although, generally, y is a function of x, in our example we can alsy say x is a function of y since y=2x is 1-1. So, taking the derivative of y=2x with respect to y, we get
dydx=21. SO, when y changes by any amount, x will change half as much.