E eiei0 New member Joined Feb 28, 2009 Messages 7 May 24, 2009 #1 I dont quite understand what this question is asking me to do: If F(x) = \(\displaystyle \int_{x}^{4x}(1/t)dt\) then F' (x)' = ? when i integrated it i got ln 4x - lnx = ln 4, but from there where do i go?
I dont quite understand what this question is asking me to do: If F(x) = \(\displaystyle \int_{x}^{4x}(1/t)dt\) then F' (x)' = ? when i integrated it i got ln 4x - lnx = ln 4, but from there where do i go?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 May 24, 2009 #2 You are asked to find the derivative of the integral. Try using this: \(\displaystyle \frac{d}{dx}\int_{h(x)}^{g(x)}f(t)dt=f(g(x))g'(x)-f(h(x))h'(x)\)
You are asked to find the derivative of the integral. Try using this: \(\displaystyle \frac{d}{dx}\int_{h(x)}^{g(x)}f(t)dt=f(g(x))g'(x)-f(h(x))h'(x)\)
E eiei0 New member Joined Feb 28, 2009 Messages 7 May 24, 2009 #3 wouldnt that just be F'(x)? why is there a ' after the (x) as well?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 May 24, 2009 #4 I don't know. Perhaps a typo?.