What is the shape of the graph?

Touch_me

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Mar 25, 2015
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Hi guys,

I still can not solve the following functions and needed help.



Wanted is a closed (start point and end point are the same), convexer functiongraph
(Convex> Links curvature (positive) f '' (x)> 0; counterclockwisedirection).
Curvature behavior of a function: Differential calculus 2nd derivative

This functiongraph consists of 13 distances (13 seconds time duration) with the length s.

In the 13 timeintervals is each distance s curved (curvature: deg/Time [°/s]), for example to 2*s [°/s],
or no curvature (Distance s is smooth) is 0 [°/s] or 0*s [°/s].
Example of the degree [°] a curvature of a distance s is "2*s [°]" or "0 [°]" or "0*s [°]".

Table of the curvature of distance s per time interval.

Time ______curvature degree / time [°/s]
1________________ {0*s [°/s]} ___ no curvature
2________________ {0*s [°/s]} ___ no curvature
3________________ {0*s [°/s]} ___ no curvature
4________________ {1*s [°/s]}
5________________ {0*s [°/s]} ___ no curvature
6________________ {2*s [°/s]}
7________________ {0*s [°/s]} ___ no curvature
8________________ {2*s [°/s]}
9________________ {1*s [°/s]}
10 _______________{2*s [°/s]}
11 _______________{0*s [°/s]} ___ no curvature
12 _______________{4*s [°/s]}
13 _______________{0*s [°/s]} ___ no curvature


From this table, is a function equation can be created with the corresponding function graph.

If the task should be somewhat unclear, please ask me!


I would be happy with simple words to get a detailed explanation, easy to understand.

Thanks advance!

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Last edited:
Nobody has an idea for a solution to a functional equation ?!

Why is this problem so difficult to understand?



I do not know if it is important for the solution.

I noticed that the curvature indices (factors) from the table
(0; 0; 0; 1; 0; 2; 0; 2 1; 2; 0; 4; 0)
the sequence of the "Proper divisor" corresponds.

The functiongraph passes through the "distance s“ pro “time interval (1 sec.)".


If you have questions about the statement of the problem, then please ask!


 
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