Yes, of course. To "anti-differentiate" (or, perhaps better, to "find the anti-derivative" of) function f, means to find all functions whose derivative is f. Since the derivative of a constant is 0, the derivative of (1/2)ln2+ 1)+c is 1/(2x+ 1)+ 0=1/(2x+ 1) for any c.when you antidifferentiate 1/(2x+1)
I get 1/2ln(2x+1) do I also have to include the constant c??
so i beomes 1/2 ln (2x+1) + c ??
when you antidifferentiate 1/(2x+1)
I get 1/2ln(2x+1) do I also have to include the constant c??
so i beomes 1/2 ln (2x+1) + c ??
when you antidifferentiate 1/(2x+1)
I get 1/2ln(2x+1) do I also have to include the constant c??
so i beomes 1/2 ln (2x+1) + c ?? That is incorrect. You left off the required absolute value bars.
when antidifferentiate 1/(2x+1)
I get 1/2ln(2x+1) do I also have to include the constant c??