Hello, I am currently stuck on a following problem: Imagine a group of children on a playground, where each child represents a point and they stand in such position, that none of 4 children stands in one line(abscissa). Then if there is no other child standing on abscissa AB, both A and B can see each other, but if there is C in between them, then A can't see B and B can't see A. What is the lowest amount of children, so that any child doesnt see atleast 1 other child? Prove it!
I think the answer is 6- a triangle with one "extended" end on each side by one point. The thing is I have no idea how to prove such thing. I would appreciate any help. Thank you very much!
I think the answer is 6- a triangle with one "extended" end on each side by one point. The thing is I have no idea how to prove such thing. I would appreciate any help. Thank you very much!