The quotient rule can't be used if the limit of the denominator is 0.
Why is that? Or is it an assumption that we just need to make?The quotient rule can't be used if the limit of the denominator is 0.
lev, isn't it true that you can't use the quotient law for limits only if the numerator and denominator are both 0?The quotient rule can't be used if the limit of the denominator is 0.
You may be right. I studied this 30 years ago. Couple of sites I looked up before posting mentioned only the denominator.lev, isn't it true that you can't use the quotient law for limits only if the numerator and denominator are both 0?
If after direct substitution you get 7/0, you are done. I think I am right but I took calculus 1 back in 1986 (just over 30 years ago) and haven't taught it (or anything) for 11 years.You may be right. I studied this 30 years ago. Couple of sites I looked up before posting mentioned only the denominator.
Look at the statement of the Quotient Law (for limits, I presume!) as given to you; if you don't see the answer, quote it to us and tell us what you think specifically about it.
I wonder if your question is about something slightly different; it reminds me of questions people often ask about asymptotes (which are another kind of limit). Are you wondering about the fact that this function equals zero infinitely many times?
Isn't g(x) = x a function? It's not a matter of how it's written, but of what it is! And any expression is a function.View attachment 24473
As long as the function in the denominator does not equal zero the quotient law works... hmm this gives me a few more conflicts.
The original question doesn't have a function in the denominator. Only a variable. Does this have an affect?
And why would the law not allow for the function to approach zero if the denominator never actually is zero?
I am not clear what you are saying. Suppose we have x−>5limx−5x. I guess this is a bit hand waving but I use the quotient law to get 5/0, so the limit dne. Where is the problem? How can I get into trouble doing this?Isn't g(x) = x a function? It's not a matter of how it's written, but of what it is! And any expression is a function.
Limits can exist when the denominator approaches zero, but you can't use this rule to find them. The proof of the theorem would show you why.
I guess it depends on whether "limit exists" includes the case of infinity.If after direct substitution you get 7/0, you are done. I think I am right but I took calculus 1 back in 1986 (just over 30 years ago) and haven't taught it (or anything) for 11 years.
I am not clear what you are saying. Suppose we have x−>5limx−5x. I guess this is a bit hand waving but I use the quotient law to get 5/0, so the limit dne. Where is the problem? How can I get into trouble doing this?
And if I get 0/0 then I try to either remove the 0/0 or I use L'Hopital's rule.
So this question is not so much about the properties of mathematics but about applying the given theorem? They intentionally left out components of the theorem to make it all encompassing?Ultimately, the reason you can't use the rule as stated (even if the numerator were 5) is because they don't include that case in their statement of the theorem! If a theorem says "if d is not zero", and d is zero, you can't apply that theorem.
Also, the theorem as stated only lets you conclude that the limit does exist; it doesn't give you a way to conclude that it does not.
They could have written that theorem to include such a case, but it would have added complications: they would have to exclude the 0/0 case; and when the limit of the denominator is zero but the numerator is not, the way in which the denominator approached zero would make a difference in whether the limit is infinite or does not exist. Consider, for example, the limit of 1/x vs. 1/x^2. It's just a lot cleaner to make that a separate theorem or set of theorems.
There's a reason I asked for the book's statement of the theorem!
(By the way, I haven't actually taught calculus since before you learned it. That's one reason I'm cautious in helping students with it, even though I tutor in it frequently.)
Huh?So this question is not so much about the properties of mathematics but about applying the given theorem? They intentionally left out components of the theorem to make it all encompassing?
I think I understand now. Thank you very muchHuh?
You can't use a property of mathematics until it has been proved. That is called a theorem. So a theorem is a property of mathematics!
But the problem you gave us explicitly says that it is asking about whether you can apply this theorem:
View attachment 24516
A particular theorem says what is true under certain circumstances. You can apply the theorem under those circumstances. You are being asked whether this limit fits those circumstances.
Nothing is "left out". Mathematics builds up from nothing (well, from axioms and definitions). Other circumstances are covered by other theorems (or by nothing at all, if those circumstances are useless). In this case, other theorems have to be applied, because "0/0" is too special a case to be included in a general theorem. An "all-encompassing" theorem would be too big and complicated to teach all at once.