Why is my Laplace Inverse wrong?

corolla

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Sep 24, 2021
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I am doing Laplace inverse here and get the following answer, but when I check online, it shows a much more elaborate answer that I don't understand. Why is my answer wrong? What steps do I take to get the correct answer?
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E-math help answer:
1700328995453.png
Symolab answer:
1700329007444.png
 
L1{easF(s)}=u(ta)f(ta), where L1{F(s)}=f(t).L^{-1}\{e^{-as}F(s)\}=u(t-a)f(t-a), \text{ where }L^{-1}\{F(s)\}=f(t).

In order to calculate f(t)f(t) you have to split 1/{(s2+4)(s+1)s}1/\{(s^{2}+4)(s+1)s\} into the partial fractions

(As+B)/(s2+4)+C/(s+1)+D/s.(As+B)/(s^{2}+4)+C/(s+1)+D/s.
 
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