jferrel8 said:The length of a retangular poster is 7ft more than the width and the diagonal of the poster is 17ft. Find the length and the width.
No; should be 17^2 = (W + 7)^2 + W^2jferrel8 said:ok i got....
17^2= 7^2 +W^2
289=49+W
240=W
is 17^2 = 49?jferrel8 said:17^2=(W+7)^2+W^2
ok now i got..... 49= (W+7)(W+7)+W^2
....49=W^2+7W+7W+49+w^2
0=2W^2+17W..... i dont know where as to go with this problem