Word problem

[RHSLilSweetie07]

Anthony leaves Kingstown at 2:00 P.M. and rives to Queensville, 160 mile distant, at 45 mph. At 2:15 P.M., Helen leaves Queensville and drives to Kingstown at 40 mph. At what time do they pass each other on the road?

Using time = distance/rate, I found that it would take 3.56 hours for Anthonly to travel the complete distance, and Helen 4 hours. What should I do from here? Is there some equation to set up?

 

[ctelady]

Anthony leaves Kingstown at 2:00 P.M. and rives to Queensville, 160 mile distant, at 45 mph. At 2:15 P.M., Helen leaves Queensville and drives to Kingstown at 40 mph. At what time do they pass each other on the road?

Together they cover the full distance of 160 miles.
A's distance + H's distance = 160
Let t = A's time, then t- .25 = H's time

45t + 40(t- .25) = 160
45t +40t -10 = 160
When you find t, add it to A's starting time for the final ans.

 

[Denis]

Anthony leaves Kingstown at 2:00 P.M. and rives to Queensville, 160 mile distant, at 45 mph. At 2:15 P.M., Helen leaves Queensville and drives to Kingstown at 40 mph. At what time do they pass each other on the road?

When Helen leaves, Anthony has already travelled for 15 min @ 45 mph,
which is 45/4 miles: so left to be travelled is (160 - 45/4) miles.

This distance will be travelled at the combined speeds, so at 85 mph.

speed = distance / time
85 = (160 - 45/4) / t
t = (160 - 45/4 / 85
t = (640 - 45) / (4*85)
t = 595 / 340
t = 1.75 hour, which is 1 hour and 45 minutes.

So they meet at 2:15 + 1:45 = 4:00