word problems: 60 quarters, dimes w/ total value $9.75
- Thread starter luist
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Re: word problems
I'll do a DIFFERENT example problem:
100 nickels and dimes were emptied from a candy machine. the total value was $8.00.how many of each type were there.
Assume we had
# of nickels = N.............................Value of N nickels = 0.05 * N
# of dimes = D...............................Value of D dimes = 0.10 * D
The problem states:
"100 nickels and dimes were emptied ..."
so
N + D = 100...................................................(1)
The problem states:
" ..the total value was $8.00 ..."
so
0.05 * N + 0.10 * D = 8...................................................(2)
from (1)
N = 100 - D...........................................................................(3)
Using (3) in (2)
0.05*(100-D) + 0.10 * D = 8............................(substitution)
5 - 0.05*D + 0.1*D = 8
0.1D - 0.05D = 8 - 5.........................................(isolation)
0.05D = 3
D = 60..................................................................................(4)
Using (4) in (3)
N = 100 - 60 = 40..................................................................(5)
So
The number nickels = 40
The number dimes = 60
Follow the exact same method to solve your problem.
luist said:
I'll do a DIFFERENT example problem:
100 nickels and dimes were emptied from a candy machine. the total value was $8.00.how many of each type were there.
Assume we had
# of nickels = N.............................Value of N nickels = 0.05 * N
# of dimes = D...............................Value of D dimes = 0.10 * D
The problem states:
"100 nickels and dimes were emptied ..."
so
N + D = 100...................................................(1)
The problem states:
" ..the total value was $8.00 ..."
so
0.05 * N + 0.10 * D = 8...................................................(2)
from (1)
N = 100 - D...........................................................................(3)
Using (3) in (2)
0.05*(100-D) + 0.10 * D = 8............................(substitution)
5 - 0.05*D + 0.1*D = 8
0.1D - 0.05D = 8 - 5.........................................(isolation)
0.05D = 3
D = 60..................................................................................(4)
Using (4) in (3)
N = 100 - 60 = 40..................................................................(5)
So
The number nickels = 40
The number dimes = 60
Follow the exact same method to solve your problem.