rachelmaddie
Full Member
- Joined
- Aug 30, 2019
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- 851
Hi. I need my work checked for this please.
The weight of the truck is directed downward. It is countered by a force normal to the plane of the hill and one that is parallel to the plane of the hill.
The magnitude of the force parallel to the hillside required to keep the the truck from rolling down the hill is:
(2600 Ib)*(sin25°) = 1098.81 Ib = 1099 Ib
The weight of the truck is directed downward. It is countered by a force normal to the plane of the hill and one that is parallel to the plane of the hill.
The magnitude of the force parallel to the hillside required to keep the the truck from rolling down the hill is:
(2600 Ib)*(sin25°) = 1098.81 Ib = 1099 Ib