Work problem

[alyren]

a developer wants to enclose a rectanguler grassy lot that borders a city street for parking. if the developer has 332 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?

is this right?
Fencing (332) = 2x+y
y=332-2x
Area = -2x(x-166)

 

[BigGlenntheHeavy]

\(\displaystyle Can \ you \ take \ it \ from \ here?\)

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[mmm4444bot]

is this right?

Fencing (332) = 2x+y Yes

y=332-2x Yes

Area = -2x(x-166) No

Why don't you start by defining your symbols x and y ? Then, perhaps, you would realize that the area is x times y.

x = width

y = length

Area = x(332 - 2x)

 

[alyren]

if i Distribute the Area = -2x(x-166) wouldn't that equal to -2x^2+332x same as A=x(332-2x), = 332x-2x^2?

 

[mmm4444bot]

if i Distribute the Area = -2x(x-166) wouldn't that equal to -2x^2+332x same as A=x(332-2x), = 332x-2x^2?

You asked if these two expressions "would not" be equal? The answer to that question is no because they are equal.

There are many factorizations of the area. Here's another: 4x^2(83/x - 1/2)

What are you doing? I mean, from where did you get the expression -2x(x - 166) ?

The area of a rectangle is length times width.

The length is 332 - 2x and the width is x.