JimmyBarns2
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- Jul 23, 2019
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Info::::: There is a lake in the Karuu Wildlife park in South Africa.
A trig function can model the depth of the water.
The water is 5.5 meters deep at the highest tide and only 1.5 meters deep at the lowest tide. There are also 14 hours between each high tide and the lake is able to be walked through when the depth of the lake is less than 2 meters.
Questions
1: Model the depth of the water at the lake and state the period when its safe to walk in the lake.
Answer:
Period is 14 hours as this is the time between each high tide. This means 2Pi/B =14 so B = 2Pi/14.
Amplitude is 5.5-1.5/2 so it's 2 metres.
Distance to mid point is 5.5 metres + 1.5 / 2 so that's 3.5 metres
and when it's safe to walk should be 14/2 so 7 hours between the low tides.
The equation would then be D = 2 cos 2pi/14 + 3.5
Would this be correct?
Many thanks.
A trig function can model the depth of the water.
The water is 5.5 meters deep at the highest tide and only 1.5 meters deep at the lowest tide. There are also 14 hours between each high tide and the lake is able to be walked through when the depth of the lake is less than 2 meters.
Questions
1: Model the depth of the water at the lake and state the period when its safe to walk in the lake.
Answer:
Period is 14 hours as this is the time between each high tide. This means 2Pi/B =14 so B = 2Pi/14.
Amplitude is 5.5-1.5/2 so it's 2 metres.
Distance to mid point is 5.5 metres + 1.5 / 2 so that's 3.5 metres
and when it's safe to walk should be 14/2 so 7 hours between the low tides.
The equation would then be D = 2 cos 2pi/14 + 3.5
Would this be correct?
Many thanks.