x(2x-x)=0...solving for x

[dayton1]

If I have: 2x^2-x^2=0. I would factor: x(2x-x)........if I am solving for x what is my next step...any help?

 

[jwpaine]

\(\displaystyle \L 2x^2\,-\,x^2\,=\, 0\)

\(\displaystyle \L x^2 = 0\)

\(\displaystyle \L x = 0\)