x^3y^3 differentiation

[sillycupcake]

Differentiate the expression x3y3 with respect to x. (Use D for dydx).


I am absolutely stuck. I am not sure if I have even came close to the right answer or not.
here is where I have gotten:
3x²(dy/dx)y³+x³(dy/dx)3y²
As for where to go from here, I am not even sure how to go from here. I am at a loss. I appreciate all the help I can get!

 

[Integrateurmum]

i'm pretty that is it. Unless it is an equation, cant do much.

 

[Deleted member 4993]

Differentiate the expression x3y3 with respect to x. (Use D for dydx).


I am absolutely stuck. I am not sure if I have even came close to the right answer or not.
here is where I have gotten:
3x² (dx/dx) y³+x³(dy/dx)3y²
As for where to go from here, I am not even sure how to go from here. I am at a loss. I appreciate all the help I can get!

d/dx(x³y³) = 3 * x² *(dx/dx) * y³ + x³ * 3 * y² * (dy/dx) = 3 * x² *(1) y³ + x³ * 3 * y² * (dy/dx) = 3 * x² *(1) y³ + x³ * 3 * y² * (dy/dx) = 3 * x² * y² * [y + x * dy/dx]

 

[Ishuda]

Differentiate the expression x3y3 with respect to x. (Use D for dydx).


I am absolutely stuck. I am not sure if I have even came close to the right answer or not.
here is where I have gotten:
3x²(dy/dx)y³+x³(dy/dx)3y²
As for where to go from here, I am not even sure how to go from here. I am at a loss. I appreciate all the help I can get!

See the red above, should be dx/dx which is equal to one otherwise what you have is correct. It would be good but, depending on the instructor/professor, not necessary to simplify it further as Subhotosh Khan has done above.