What kind of DE is this y'=(1-xy)^(1/2) how to solve it? thx
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Nov 4, 2006 #2 I would say integrate both sides: \(\displaystyle \L\\\int{\frac{dy}{dx}}=\int\sqrt{1-xy}dx\) \(\displaystyle \L\\y=\frac{-2(1-xy)^{\frac{3}{2}}}{3y}+C\)
I would say integrate both sides: \(\displaystyle \L\\\int{\frac{dy}{dx}}=\int\sqrt{1-xy}dx\) \(\displaystyle \L\\y=\frac{-2(1-xy)^{\frac{3}{2}}}{3y}+C\)
G Guest Guest Nov 11, 2006 #3 If I differentiate your solution, does it back to y'=(1-xy)^(1/2) ???? Thanks :wink:
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Nov 12, 2006 #4 atomos said: If I differentiate your solution, does it [result in] y' = (1 - xy)^(1/2) ? Click to expand... Differentiate and find out. Eliz.
atomos said: If I differentiate your solution, does it [result in] y' = (1 - xy)^(1/2) ? Click to expand... Differentiate and find out. Eliz.