Hi there,
I've been trying to do a sum but I'm not succeeding in solving the sum no matter how much I try.
We have to form a differential equation by eliminating arbituary values from the given equation.
Given equation y=ax^3 + bx^2
The solution (it's given after the exercise) is :
\(\displaystyle 6.\, x^2\,\dfrac{d^2y}{dx^2}\, -\, 4x\, \dfrac{dy}{dx}\, +\, 6y\, =\, 0\)
Thank you for your concern.
I've been trying to do a sum but I'm not succeeding in solving the sum no matter how much I try.
We have to form a differential equation by eliminating arbituary values from the given equation.
Given equation y=ax^3 + bx^2
The solution (it's given after the exercise) is :
\(\displaystyle 6.\, x^2\,\dfrac{d^2y}{dx^2}\, -\, 4x\, \dfrac{dy}{dx}\, +\, 6y\, =\, 0\)
Thank you for your concern.
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