D daiyo New member Joined May 5, 2011 Messages 2 May 5, 2011 #1 y' = xe^(x+y) So I know you have to take the natural log of both sides. ln y' = (x+y) ln x Then I'm stuck. Help please? Thanks
y' = xe^(x+y) So I know you have to take the natural log of both sides. ln y' = (x+y) ln x Then I'm stuck. Help please? Thanks
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 May 5, 2011 #2 daiyo said: So I know you have to take the natural log of both sides. Click to expand... Why would you do that? \(\displaystyle y' = x\cdot e^{x+y} = x\cdot e^{x}\cdot e^{y}\) It's Separable!
daiyo said: So I know you have to take the natural log of both sides. Click to expand... Why would you do that? \(\displaystyle y' = x\cdot e^{x+y} = x\cdot e^{x}\cdot e^{y}\) It's Separable!
D daiyo New member Joined May 5, 2011 Messages 2 May 5, 2011 #3 Oh ok so you would do: S = integral sign S(y'/e^y) = S (xe^x)
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 May 5, 2011 #4 I think you have it. Let's see what you get.
