How do I separate this or solve this to find the general solution? y' = ye^x - 2e^x + y - 2
T ttn181 New member Joined Mar 30, 2011 Messages 3 Mar 30, 2011 #1 How do I separate this or solve this to find the general solution? y' = ye^x - 2e^x + y - 2
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Mar 31, 2011 #2 Factor the right side: \(\displaystyle \frac{dy}{dx}=e^{x}(y-2)+(y-2)\) Now, continue?.
