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  • logistic_guy
    logistic_guy replied to the thread amplifier.
    0.2 = V\frac{1000}{R_T + 1000} 0.2 = V\frac{1000}{100 + 1000} This gives: V = \textcolor{blue}{0.22 \ \text{V}}
  • logistic_guy
    logistic_guy replied to the thread microprocessor - 1D.
    \bold{8.} Convert an \text{8B07H} \text{f}rom machine language to assembly language. \textcolor{blue}{\text{MOV AX},[\text{BX}]}
  • logistic_guy
    logistic_guy replied to the thread microprocessor - 6.
    \bold{8.} Convert the following octal numbers into decimal: (c) 7767.07 = 7(8^3) + 7(8^2) + 6(8^1) + 7(8^0) + 0 + 7(8^{-2}) =...
  • logistic_guy
    logistic_guy replied to the thread puzzle - 2.
    \textcolor{darkred}{\bold{COMPANY}} \longrightarrow \textcolor{grey}{\bold{Co}} \huge\textcolor{indigo}{\bold{the \ solution \ so \ far.}}
    • image38.jpg
  • logistic_guy
    logistic_guy replied to the thread IAS computer.
    Let us start with the content 010\text{FA}210\text{FB}. We take the first half, 010\text{FA}. So this gives us the operation code 01...
  • logistic_guy
    logistic_guy replied to the thread transistor - 2.
    🙁🙁 v_o + V_{CE} - 5000I_3 - 9 = 0 v_o + V_{CE} - 5000(-I_C) - 9 = 0 0.0490842 + V_{CE} + 5000(0.0001221) - 9 = 0 V_{CE} = 9 -...
  • K
    How do you know that??! Show work.
  • logistic_guy
    \ \bold{8.} List the desirable characteristics of a benchmark program. A \textcolor{indigo}{\bold{benchmark \ program}} is software...
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