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logistic_guy replied to the thread supported beam.We are being lazier than an \textcolor{black}{\bold{orange}} \ \textcolor{orange}{\bold{cat}}. At this time, we will calculate the... -
logistic_guy replied to the thread exact - 5.Let M = -xy\sin x + 2y\cos x And N = 2x\cos x Then, \frac{\partial M}{\partial y} = (-x\sin x + 2\cos x) \neq (-2x\sin x + 2\cos...
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logistic_guy replied to the thread matrix exponential.The question wants us to find e^{\bold{A}t} when \bold{A} = \begin{pmatrix} 2 & 0 \\ 0 & 3 \end{pmatrix}...
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SShakermt replied to the thread Finding lbs per inch of a load.So I used that spreadsheet for 4 years now and it has worked so good. But now I have moved up in truck and trailer. I now drive a 4 axle...
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logistic_guy reacted to pazzy78's post in the thread Differential Equation, not getting correct answer can't see why ... with
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Thanks, sorry got it out when I did the u sub ... sorry silly question should have known the coefficient of variable should be 1... -
Ppazzy78 reacted to logistic_guy's post in the thread Differential Equation, not getting correct answer can't see why ... with Like.
Yes. Basically, you need to do this: \int\frac{1}{g + 0.098v^2} \ dv =...
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Ppazzy78 replied to the thread Differential Equation, not getting correct answer can't see why ....Thanks, sorry got it out when I did the u sub ... sorry silly question should have known the coefficient of variable should be 1...
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logistic_guy replied to the thread Differential Equation, not getting correct answer can't see why ....Yes. Basically, you need to do this: \int\frac{1}{g + 0.098v^2} \ dv =...
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Ppazzy78 reacted to logistic_guy's post in the thread Differential Equation, not getting correct answer can't see why ... with Like.
We need to get rid of g because we want the integral to look like this after the substitution: \int \frac{1}{1 + u^2} \ du = \tan^{-1}...
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Ppazzy78 replied to the thread Differential Equation, not getting correct answer can't see why ....OK seems I need to do a u sub as the coefficient of x^2 [in this case v^2] needs to be 1...
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logistic_guy replied to the thread Differential Equation, not getting correct answer can't see why ....We need to get rid of g because we want the integral to look like this after the substitution: \int \frac{1}{1 + u^2} \ du = \tan^{-1}...
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Ppazzy78 replied to the thread Differential Equation, not getting correct answer can't see why ....^^ Why do you need to get rid of the g ? surely it is just a constant ?
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logistic_guy replied to the thread Differential Equation, not getting correct answer can't see why ....\int\frac{1}{g + 0.098v^2} \ dv How to solve this integral? First, you get rid of the g. \int\frac{1}{g + 0.098v^2} \ dv =...
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Ppazzy78 replied to the thread Differential Equation, not getting correct answer can't see why ....I still don't understand ... where do i need to divide by sqrt(.098)..? 1/(root g) = 0.3194.... (0.313(v)/root g) when v = 120 =...
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logistic_guy replied to the thread Differential Equation, not getting correct answer can't see why ....t \neq \frac{1}{\sqrt{g}} \tan^{-1}12 You forgot to divide by \sqrt{0.098}. t = \frac{1}{\sqrt{g}\sqrt{0.098}} \tan^{-1}12 😉😉