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JIf a were 3y and b were -1, then you'd have (a - b)^2 = ((3y) - (-1))^2 =(3y)^2 - 2(3y)(-1) + (-1)^2 = 9y^2+6y+1. But that's (3y+1)^2...
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Jjpanknin replied to the thread Polynomial Special Product Formula.That second line is what I needed. Thank you.
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Dr.Peterson replied to the thread Polynomial Special Product Formula.If a were 3y and b were -1, then you'd have (a - b)^2 = ((3y) - (-1))^2 =(3y)^2 - 2(3y)(-1) + (-1)^2 = 9y^2+6y+1. But that's (3y+1)^2... -
jonah2.0 replied to the thread Polynomial Special Product Formula.Beer drenched reaction follows. Welcome back. Long time no see. -
BeachBanana replied to the thread Polynomial Special Product Formula.b=1 works fine. -
BeachBanana replied to the thread Polynomial Special Product Formula.Because b=1 not -1.
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JThe formula is (a - b)^2 = a^2 - 2ab + b^2. For the following equation, why does the second term (-1) not get put into the formula as a...
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TTed replied to the thread Calculus Exam Preparation: Complete Study Guide.I've approved this thread if the poster wishes to contribute further useful study guide information, but have removed unsolicited links...
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Trigonometric Derivatives d/dx[sin(x)] = cos(x) d/dx[cos(x)] = -sin(x) d/dx[tan(x)] = sec²(x) d/dx[csc(x)] = -csc(x)cot(x) d/dx[sec(x)]... -
Dr.Peterson replied to the thread Probability.Please show us what you have tried, and where you are stuck; we don't just solve problem for you, but with you. Also, are "you" male or...
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K“Mr. Khoa has devised a new method for giving bonus points to students in his math class as follows: He randomly selects 4 male...
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Ffresh_42 replied to the thread Bath filling problem.I was taught this subject as three methods of solving linear equations: substitution, addition, and one I have forgotten the name of and...
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Ccohen27 replied to the thread Bath filling problem.Dear Fresh_42, I'll try and make sense of it. Can I ask the best way to begin learning and manipulating linear equations for a complete...
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K\begin{array}{lll} a+b&=\dfrac{1}{4}\\[8pt] a+c&=\dfrac{1}{5}\\[8pt] b&=2c \end{array} The first step was to plug in b from (3) into...
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Ffresh_42 replied to the thread Bath filling problem.\begin{array}{lll} a+b&=\dfrac{1}{4}\\[8pt] a+c&=\dfrac{1}{5}\\[8pt] b&=2c \end{array} The first step was to plug in b from (3) into...
