Latest activity
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TTed replied to the thread bad moderating!.The boards were effectively without moderation for a project period. I've been keeping a closer eye on it, but will likely shift...
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XThis is a recurring topic in this forum. My answer: there is no 1^\infty or \frac{0}{0}. Those symbols are occasionally used as names of...
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Xxamidi reacted to Mondo's post in the thread Logo (the Pythagorean theorem on the logo is wrong it's supposed to be a^2 + b^2 = c^2) with
Like.
I never paid attention to the formula in the logo but I must agree with the claim - it is misleading. The fact that it is right below... -
Xxamidi reacted to a2+b2=c2's post in the thread Logo (the Pythagorean theorem on the logo is wrong it's supposed to be a^2 + b^2 = c^2) with Like.
Actually, I agree with LL345. This is because if you say leg^2 + leg^2, it will seem like both sides are ALWAYS the same, which is...
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Xxamidi reacted to LL345's post in the thread Logo (the Pythagorean theorem on the logo is wrong it's supposed to be a^2 + b^2 = c^2) with Like.
Idk looks pretty 90° to me ¯\_(ツ)_/¯ It seems like you just came up with an excuse for bad logo design.
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XIt's sad to see AI basically taking over the academic arena. AI doing the math work for students can't lead to academic progress...
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Xxamidi replied to the thread bad moderating!.My first two postings were finally approved. It took at least 5 weeks, but due to the non-functioning board I stayed away and only...
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Aaskan replied to the thread Checking for radical equation.The problem, and it's solution is from a course I am doing on Algebra 1 & 2. Here's the problem as stated So I have three issues...
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Aaskan replied to the thread Rational exponent.So I am guessing the issue is still that there are two possible values for square root, which is fundamentally against algebra where one...
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Dr.Peterson replied to the thread Lottery.Do you think it's easy? I think some of the others are a little more straightforward. Have you worked it out yet, either from the... -
Dr.Peterson replied to the thread Rational exponent.See my answer to your other question. The second question here is worth pondering. Can you see why using the negative root might cause...
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Dr.Peterson replied to the thread Checking for radical equation.What is the problem you are solving? And where did you get this work that you evidently disagree with? Coming into a discussion after...
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ACouldn't the square root of 4 have equaled to -2? That would have made x = 2 a solution for the equation
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Aaskan replied to the thread Rational exponent.Why are you treating it as a function? And why prefer the positive value over the negative one for the function's correspondence?
