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KWith the sketch marked up the way I have done above, you might then see a more direct (& elegant?) way to determine the lengths of x &...
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CWith the sketch marked up the way I have done above, you might then see a more direct (& elegant?) way to determine the lengths of x &...
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BBilly_B replied to the thread Circles and Sine Waves.Thanks Dr Peterson for your answer and ref to GeoGebra. I’ll look for some Youtube tutorials. Reason for asking is: It’s an idea/theory...
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Dr.Peterson replied to the thread Circles and Sine Waves.Of course it would not literally be a sine wave, since a sine wave has a fixed amplitude. It would be some variation, along the lines of... -
The Highlander replied to the thread areas in regular octagon.So am I but that's not a problem either because you can teach an old dog new tricks! 😉😊 -
shahar replied to the thread areas in regular octagon.Thanks, it warn my heart. Thank you. I meant the my hair dye is black and white because I am old. -
Not a problem, I know English is not your native tongue (Hebrew, is I believe?) and that English is a very difficult language to master...
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The Highlander replied to the thread Trigonometry problem.With the sketch marked up the way I have done above, you might then see a more direct (& elegant?) way to determine the lengths of x &...
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The Highlander replied to the thread areas in regular octagon.Not a problem, I know English is not your native tongue (Hebrew, is I believe?) and that English is a very difficult language to master...
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Cchijioke replied to the thread Trigonometry problem.I am now very cleared. Thank you so much.
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shahar replied to the thread areas in regular octagon.Yes. I do my Math matriculation in 2000. So, Now as Adult I forgot many things. I tried to edit your message and to put in, but I very...
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KI'm afraid that is very poorly written out! ☹️ I'm doubtful if it would gain you anything close to full marks in a test but (I think)...
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The Highlander replied to the thread areas in regular octagon.I'm afraid that is very poorly written out! ☹️ I'm doubtful if it would gain you anything close to full marks in a test but (I think)...
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shahar replied to the thread areas in regular octagon.Yes. The first blank space is l^2 tbe -nd is 1/2 * l * l = (l^2)/2 s^2 = 2l^2 in the -rd is 1/2(4 * l^2) = 2l^2 now, Areas are equal.
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The Highlander replied to the thread Trigonometry problem.Yes, that is the symbol for a right angle and, although the altitude appears to bisect the apex, it clearly does not (as seen by the...
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