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NPossibly you are comparing these: But those agree: \frac{dr}{dx} = e^{xy \ln(x)}({\color{Green}{y\ln x + xy'\ln x + y}}) =...
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NPlease show explicitly the two things you say are different. What thing that you wrote, and what thing that someone else wrote, do you...
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Nnasi112 replied to the thread Showing that the sum of cubes of an arithmetic progression is divisible by the sum of its terms.Why you did not use the direct evidence? \frac{T}{S} = \frac{\sum_{k=0}^{n-1}(a + kd)^3}{\sum_{k=0}^{n-1}(a + kd)} =...
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AAion replied to the thread Showing that the sum of cubes of an arithmetic progression is divisible by the sum of its terms.This approach resolves the earlier difficulty I had with directly factoring the expanded expression. In particular, instead of trying to...
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AAion replied to the thread Showing that the sum of cubes of an arithmetic progression is divisible by the sum of its terms.Thank you for letting me know. I wasn’t entirely sure which forum category was most appropriate for the problem.
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Llookagain replied to the thread Showing that the sum of cubes of an arithmetic progression is divisible by the sum of its terms.Your topic problem (and demonstration of the attempt of the answer) belong under the forum "Intermediate/Advanced Algebra."
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Sscottbrandon replied to the thread Probability that a credit card expires within a given 12 months.Each card has 36 months total life so the probability of expiration in any given month is 1/36 or about 2.78%. Applied to 100 contracts...
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AAion posted the thread Showing that the sum of cubes of an arithmetic progression is divisible by the sum of its terms in Beginning Algebra.Find the sum of the cubes of the terms of an arithmetic progression and show that it is exactly divisible by the sum of the terms...
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TTygra replied to the thread Help with Second Order Differential Equation with Two Dependent Variables.Thank you.
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Sscottbrandon replied to the thread integration for engineering students.I’d recommend Neso Academy on YouTube. It explains integration in a very engineering-focused way with examples from circuits, signals...
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Ffresh_42 replied to the thread Help with Second Order Differential Equation with Two Dependent Variables.In this case change the sign and solve -ay'''(x)-(1-b)y'(x)+q=0. The result is basically the same, just with b-1 instead. b=1 has...
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TTygra replied to the thread Help with Second Order Differential Equation with Two Dependent Variables.Hi fresh_42, that is great, thanks. However, for alpha, in my actual problem I am solving b is greater than 1. So I get an error when I...
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Great question. The easiest way to see it is just by following the math pattern backwards: 3! = 6 2! = 6 / 3 = 2 1! = 2 /... -
Ffresh_42 replied to the thread Help with Second Order Differential Equation with Two Dependent Variables.The essential path is to eliminate one ot the two functions and solve the resulting differential equation. Before I answer, and we...
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Kkurksai replied to the thread Factorial of zero.Great question. The easiest way to see it is just by following the math pattern backwards: 3! = 6 2! = 6 / 3 = 2 1! = 2 /...
