Integration

[posim]

Can anyone help me with this?
I need to integrate sin(sqrt x) / sqrt x
a= 0+ and b= pi^2
The sqrt and pi^2 is confusing me..

 

[srmichael]

Use u-substitution. Let \(\displaystyle u=\sqrt{x}\) then go from there.

The \(\displaystyle \pi^2\) is just a number like anything else.

 

[kloma]

Im newbie but sin ln (sqrt x) + C is my guess

 

[srmichael]

Im newbie but sin ln (sqrt x) + C is my guess

Not quite.

\(\displaystyle u=\sqrt{x}\)

\(\displaystyle du=\frac{1}{2\sqrt{x}}dx\)

\(\displaystyle dx=2\sqrt{x}du\)

Rewrite the integral in terms of "u" (and change the integral limts to reflect what "u" equals) and the go from there.

Can you take it from there????

 

[posim]

Im newbie but sin ln (sqrt x) + C is my guess

my answer was close to this also.

mmmmm
x= pi^2 u = sqrt pi^2 = pi
x= 0+ = sqrt 0 =0

(sin/u)du = [sin ln |u| ] pi 0
= sin ln pi - sin ln 0
baaah