Carmen8722
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- Feb 27, 2012
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How to find and solve the equation of a circle with radius 5 radical 2 and center (-3,2)???
How to find and solve the equation of a circle with radius 5 radical 2 and center (-3,2)???
Standard equation of a circle is:
\(\displaystyle (X-H)^2 + (Y-K)^2 \:=\: R^2\)
So you would fill in;
\(\displaystyle (-3 - H)^2 + (2 - K)^2 \:=\: 25\)
How to find and solve the equation of a circle with radius 5 radical 2 and center (-3,2)???
The general form for the equation of a circle with center (h, k) and radius r is
(x - h)2 + (y - k)2 = r2
You are GIVEN the center: (-3, 2) so if (h, k) = (-3, 2) then h = -3 and k = 2.
You are GIVEN that the radius is 5 sqrt(2)...that's r.
The equation of the circle in standard form, then, is
(x - (-3))2 + (y - 2)2 = [5 sqrt(2)]2
Can you do some simplification?
'
He's right, I got the equation mixed up, the answer would be;
\(\displaystyle (X + 3)^2 + (Y - 2)^2 \:=\: 25\)