G gomati New member Joined Jul 31, 2012 Messages 1 Jul 31, 2012 #1 let x>1,y>1 and (lnx)2 +(lny)2= lnx2 + lny2, then find the maximum value of xlny. 2. prove that ; 4 sin270 = (5+51/2 )1/2 -(3-51/2).
let x>1,y>1 and (lnx)2 +(lny)2= lnx2 + lny2, then find the maximum value of xlny. 2. prove that ; 4 sin270 = (5+51/2 )1/2 -(3-51/2).
D Deleted member 4993 Guest Jul 31, 2012 #2 gomati said: let x>1,y>1 and (lnx)2 +(lny)2= lnx2 + lny2, then find the maximum value of xlny. 2. prove that ; 4 sin270 = (5+51/2 )1/2 -(3-51/2). Click to expand... These are pretty interesting problems. For the first one - I would start with substitution:A lnx = m and lny = n An interesting observation xlny = ylnx for all x,y >1 Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
gomati said: let x>1,y>1 and (lnx)2 +(lny)2= lnx2 + lny2, then find the maximum value of xlny. 2. prove that ; 4 sin270 = (5+51/2 )1/2 -(3-51/2). Click to expand... These are pretty interesting problems. For the first one - I would start with substitution:A lnx = m and lny = n An interesting observation xlny = ylnx for all x,y >1 Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Jul 31, 2012 #3 Whoops -- It looks like you somehow missed reading our FORUM GUIDELINES. Please check 'em out, before proceeding to post again. :cool:
Whoops -- It looks like you somehow missed reading our FORUM GUIDELINES. Please check 'em out, before proceeding to post again. :cool: