Adding Fractions

[Jason76]

\(\displaystyle \dfrac{x^4}{64}+\dfrac{1}{2}+\dfrac{4}{x^4}\)

The first step is to find the LCD which is \(\displaystyle 128x^{4}\)

What next?

 

[Deleted member 4993]

\(\displaystyle \dfrac{x^4}{64}+\dfrac{1}{2}+\dfrac{4}{x^4}\)

The first step is to find the LCD which is \(\displaystyle 128x^{4}\)

What next?

Do you know how to add:

\(\displaystyle \dfrac{1}{64} \ + \ \dfrac{1}{2} \ + \ 4\)

same process...

for a quick review of the arithmetic - go to:

http://www.purplemath.com/modules/rtnladd.htm

 

[Jason76]

Do you know how to add:

\(\displaystyle \dfrac{1}{64} \ + \ \dfrac{1}{2} \ + \ 4\)

same process...

for a quick review of the arithmetic - go to:

http://www.purplemath.com/modules/rtnladd.htm

GCF would be 64 so

\(\displaystyle \dfrac{x^{4}}{64} + \dfrac{32}{64} - \dfrac{256(x^{4})}{64} = \dfrac{288(x^{4})}{64}\)

 

[MarkFL]

\(\displaystyle \dfrac{x^4}{64}+\dfrac{1}{2}+\dfrac{4}{x^4}\)

The first step is to find the LCD which is \(\displaystyle 128x^{4}\)

What next?

Your LCD would be \(\displaystyle 64x^4\) so you would have:

\(\displaystyle \dfrac{x^4}{64}\cdot\dfrac{x^4}{x^4}+\dfrac{1}{2} \cdot\dfrac{32x^4}{32x^4}+\dfrac{4}{x^4} \cdot\dfrac{64}{64}=\)

\(\displaystyle \dfrac{x^8}{64x^4}+\dfrac{32x^4}{64x^4}+\dfrac{256}{x^4}=\dfrac{x^8+32x^4+256}{64x^4}=\left(\dfrac{x^4+16}{8x^2} \right)^2\)

 

[Jason76]

Your LCD would be \(\displaystyle 64x^4\) so you would have:

\(\displaystyle \dfrac{x^4}{64}\cdot\dfrac{x^4}{x^4}+\dfrac{1}{2} \cdot\dfrac{32x^4}{32x^4}+\dfrac{4}{x^4} \cdot\dfrac{64}{64}=\)

\(\displaystyle \dfrac{x^8}{64x^4}+\dfrac{32x^4}{64x^4}+\dfrac{256}{x^4}=\dfrac{x^8+32x^4+256}{64x^4}=\left(\dfrac{x^4+16}{8x^2} \right)^2\)

Ok, thanks, got it.

 

[Deleted member 4993]

GCF would be 64 so

\(\displaystyle \dfrac{x^{4}}{64} + \dfrac{32}{64} - \dfrac{256(x^{4})}{64} = \dfrac{288(x^{4})}{64}\) ..............Incorrect

Which problem are you trying to solve?

Did you go to the web-page I had referred to?

 

[Jason76]

Which problem are you trying to solve?

Did you go to the web-page I had referred to?

I went to the webpage and understand what's going on.

(Post edited from what I had before)

First of all find the LCD. Next, do algebra (or think in your head) to find out which missing number (x) (when multiplied to the denominator) will make the LCD appear. Next, multiply that missing number to the denominator and numerator. Finally, add (or subtract, add/subtract) the numerators to get the final answer. The same steps would also be used for subtracting fractions.