K khryss New member Joined May 8, 2013 Messages 4 May 8, 2013 #1 lim (1/x)-(1/3) / (x-3) x-> 3 the answer is -1/9 but I get something different when I try...
MarkFL Super Moderator Staff member Joined Nov 24, 2012 Messages 3,021 May 8, 2013 #2 Try multiplying the expression by \(\displaystyle 1=\dfrac{3x}{3x}\) to clear the denominators in the numerator.
Try multiplying the expression by \(\displaystyle 1=\dfrac{3x}{3x}\) to clear the denominators in the numerator.
L lookagain Elite Member Joined Aug 22, 2010 Messages 3,250 May 9, 2013 #4 khryss said: lim (1/x)-(1/3) / (x-3) x-> 3 the answer is -1/9 but I get something different when I try... Click to expand... khryss, you must type the problem with grouping symbols around the numerator, such as (but not limited to) these: lim (x -> 3) ((1/x) - (1/3))/(x - 3) or lim(x -> 3) [(1/x) - (1/3)]/(x - 3) This is the equivalent of the intended expression that you are after: \(\displaystyle \displaystyle\lim_{x \to 3} \bigg(\dfrac{\frac{1}{x} - \frac{1}{3}}{ \ x - 3 \ }\bigg)\)
khryss said: lim (1/x)-(1/3) / (x-3) x-> 3 the answer is -1/9 but I get something different when I try... Click to expand... khryss, you must type the problem with grouping symbols around the numerator, such as (but not limited to) these: lim (x -> 3) ((1/x) - (1/3))/(x - 3) or lim(x -> 3) [(1/x) - (1/3)]/(x - 3) This is the equivalent of the intended expression that you are after: \(\displaystyle \displaystyle\lim_{x \to 3} \bigg(\dfrac{\frac{1}{x} - \frac{1}{3}}{ \ x - 3 \ }\bigg)\)