Let U= {q,r,s,t,u,v,w,x,y,z}
A = {q,s,u,w,y}
B= {q,s,y,z}
C= {v,w,x,y,z}
(A union B')' intersect C'
Would this end up being a null set. I'm really confused on this problem with the 3 primes.
(A union B')' intersect C'
True, and the easiest way to do this problem. But I suspect it would confuse gardenia even more. Probably better, as Subhotosh Khan suggested, to do each part, step by step.\(\displaystyle (A\cup B')'=A'\cap B\), so \(\displaystyle (A \cup B')' \cap C'=A'\cap B\cap C'\)
\(\displaystyle U\:=\: \{q,r,s,t,u,v,w,x,y,z\}\)
\(\displaystyle A\:=\:\{q,s,u,w,y\}\)
\(\displaystyle B\:=\: \{q,s,y,z\}\)
\(\displaystyle C\:=\:\{v,w,x,y,z\}\)
\(\displaystyle \text{Find: }\: (A \cup B')' \cap C'\)
Would this end up being a null set? . Yes!