ibanez1608
New member
- Joined
- Jul 12, 2013
- Messages
- 24
when does
g(x)=(-m-1)x+3<f(x)=(m=1)x2+(m-3)x+3m+1
i got the equation:
(1-m)x2+(2-2m)x-3m+2<0
the answer is m>=1
how can it be???? i dont know if X is +/-
g(x)=(-m-1)x+3<f(x)=(m=1)x2+(m-3)x+3m+1
i got the equation:
(1-m)x2+(2-2m)x-3m+2<0
the answer is m>=1
how can it be???? i dont know if X is +/-