J Jason76 Senior Member Joined Oct 19, 2012 Messages 1,180 Nov 2, 2013 #1 Post Edited \(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{18}{24}\) \(\displaystyle x = -\dfrac{3}{4}\) Last edited: Nov 2, 2013
Post Edited \(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{18}{24}\) \(\displaystyle x = -\dfrac{3}{4}\)
stapel Elite Member Joined Feb 4, 2004 Messages 16,543 Nov 2, 2013 #2 Jason76 said: \(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{24}{18}\) Click to expand... How did you divide -18 by 24 and get 24/-18? :shock: To learn how to solve simple linear equations, try here.
Jason76 said: \(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{24}{18}\) Click to expand... How did you divide -18 by 24 and get 24/-18? :shock: To learn how to solve simple linear equations, try here.
J Jason76 Senior Member Joined Oct 19, 2012 Messages 1,180 Nov 2, 2013 #3 \(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{18}{24}\) \(\displaystyle x = -\dfrac{3}{4}\)
\(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{18}{24}\) \(\displaystyle x = -\dfrac{3}{4}\)
stapel Elite Member Joined Feb 4, 2004 Messages 16,543 Nov 3, 2013 #4 Jason76 said: \(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{18}{24}\) \(\displaystyle x = -\dfrac{3}{4}\) Click to expand... What were the instructions? What are you supposed to be doing? What is your question?
Jason76 said: \(\displaystyle 24x + 18 = 0\) \(\displaystyle 24x = -18\) \(\displaystyle x = -\dfrac{18}{24}\) \(\displaystyle x = -\dfrac{3}{4}\) Click to expand... What were the instructions? What are you supposed to be doing? What is your question?