K kitty New member Joined Nov 6, 2013 Messages 2 Nov 6, 2013 #1 hi i am unable to solve this problem ,,, if x ,y ,z are in continued proportion prove that (x+y)^2/(y+z)^2=x/z
hi i am unable to solve this problem ,,, if x ,y ,z are in continued proportion prove that (x+y)^2/(y+z)^2=x/z
D daon2 Full Member Joined Aug 17, 2011 Messages 999 Nov 6, 2013 #2 I had to google "continued proportion". I don't know what you already know, you have shown no work. Am I to assume you don't know \(\displaystyle (x+y)^2=x^2+2xy+y^2\)?
I had to google "continued proportion". I don't know what you already know, you have shown no work. Am I to assume you don't know \(\displaystyle (x+y)^2=x^2+2xy+y^2\)?
K kitty New member Joined Nov 6, 2013 Messages 2 Nov 6, 2013 #3 i know (x+y)^2=x^2 +y^2+2xy but this problem is where its told they are in continued proportion meaning x/y=y/z and i am unable to do the above prove Last edited: Nov 6, 2013
i know (x+y)^2=x^2 +y^2+2xy but this problem is where its told they are in continued proportion meaning x/y=y/z and i am unable to do the above prove
D daon2 Full Member Joined Aug 17, 2011 Messages 999 Nov 6, 2013 #4 kitty said: i know (x+y)^2=x^2 +y^2+2xy but this problem is where its told they are in continued proportion meaning x/y=y/z z=y^2/x and i am unable to do the above prove Click to expand... Hint: \(\displaystyle y^2=xz\). Make some substitutions and do some factoring.
kitty said: i know (x+y)^2=x^2 +y^2+2xy but this problem is where its told they are in continued proportion meaning x/y=y/z z=y^2/x and i am unable to do the above prove Click to expand... Hint: \(\displaystyle y^2=xz\). Make some substitutions and do some factoring.