Please start your own thread rather than tacking on to the end od someone else's thread..I am lost on Quadratic equations I have to solve this one by factoring please tell me if I have this right.
z2 +z=2
(z+1) (z-1)=2 Oh no (z + 1)(z - 1) = z(z - 1) + 1(z - 1) = z^2 - z + z - 1 = z^2 - 1 = z^2 - 1^2
z=-1 or z=1 I see where you are lost.
Have you never actually taken an algebra class? First, \(\displaystyle z^2+ z\) does NOT factor as (z- 1)(z+ 1). Multiplying those gives \(\displaystyle z^2- 1\). \(\displaystyle z^2+ z\), because there is at least one "z" in each term, factors as z(z+ 1).I am lost on Quadratic equations I have to solve this one by factoring please tell me if I have this right.
z2 +z=2
(z+1) (z-1)=2
z=-1 or z=1