limit of cosh and sinh

A

azreal

New member
Joined
Nov 2, 2013
Messages
5
I want to show that for all k∈N\displaystyle k \in \mathbb{N}
lim⁡t→∞t−kcosh(t)=lim⁡t→∞t−ksinh(t)=∞\displaystyle \lim_{t \rightarrow \infty} t^{-k} cosh(t) = \lim_{t \rightarrow \infty} t^{-k} sinh(t) = \infty
I've tried to use the definition of cosh and sinh, but this didn't get my very far...
 
azreal said:
I want to show that for all k∈N\displaystyle k \in \mathbb{N}
lim⁡t→∞t−kcosh(t)=lim⁡t→∞t−ksinh(t)=∞\displaystyle \lim_{t \rightarrow \infty} t^{-k} cosh(t) = \lim_{t \rightarrow \infty} t^{-k} sinh(t) = \infty
I've tried to use the definition of cosh and sinh, but this didn't get my very far...
Click to expand...
How far did you get? Please show your working. Thank you! ;)
 
You must log in or register to reply here.
Top