Differential Skills Test (Derivatives, Chain Rule, Etc. HELP)

[liliana16cruz]

f(x) = ³√(cos⁵(sin4x)/sec(cot(√x)))

Where do I even start!? If someone can please just give me step-by-step instructions as to how to solve this, I'd be super grateful! It's something I've been struggling for weeks with and need to pass an exam with this one question in order to pass calculus 1. We have never had a question like this before in class so this is why I'm asking. I'm usually a B+ math student as well!

here is my current work:

1/3 * (cos⁵(sin4x)/sec(cot(√x)))^{-2/3 *} d/dx (cos⁵(sin4x)/sec(cot(√x)))
1/3 * (cos⁵(sin4x)/sec(cot(√x)))^{-2/3 *} sec(cot(√x))(-5sin⁴(sin4x) - (cos⁵(sin4x)(sec(cot(√x))tan(cot(√x)) / (sec(cot(√x)))²

 

[Deleted member 4993]

³√cos⁵(sin4x)/sec(cot(√x))

Where do I even start!? If someone can please just give me step-by-step instructions as to how to solve this, I'd be super grateful! It's something I've been struggling for weeks with and need to pass an exam with this one question in order to pass calculus 1. We have never had a question like this before in class so this is why I'm asking. I'm usually a B+ math student as well!

Write the question carefully -

Is the cube-root over both the numerator and the denominator?

Is that sin(4x) or sin⁴(x)?

Start by using power law of differentiation - converting ³√ to ()^1/3

Also you would need to use quotient rule and chain rule and product rule.

Please share your work with us ...

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting