rajemessage
New member
- Joined
- Aug 9, 2014
- Messages
- 15
Dear All,
There are three numbers they can have two status "a" or "b".
except 1 , 1 will have only one state "a".
only one status can exist at one time for a number.
I have to chose three number(1,2,3) , they will be in this order only.
, so please tel how many combination
can be there?
1(a)
2(a)
2(b)
3(a)
3(b)
yours sincerley
new formulation
--------------------
It is bit different,with your permition,i am taking this apartunity to make some changes.
1 2 3 will always be in this order {123}, i want to find out number of cases can be made,
like {1},{2},{23},{13},{12},{123}{3},{}. but each number has two states like "a" "b", i.e, each one will become different entity,like 2a,2b,3a,3b,1a,
with only exception i.e. 1 will have only one state 1a.
please tel me step wise using formulas, so that i can understand, also any link will be helpfull.
yours sincerly
There are three numbers they can have two status "a" or "b".
except 1 , 1 will have only one state "a".
only one status can exist at one time for a number.
I have to chose three number(1,2,3) , they will be in this order only.
, so please tel how many combination
can be there?
1(a)
2(a)
2(b)
3(a)
3(b)
yours sincerley
new formulation
--------------------
It is bit different,with your permition,i am taking this apartunity to make some changes.
1 2 3 will always be in this order {123}, i want to find out number of cases can be made,
like {1},{2},{23},{13},{12},{123}{3},{}. but each number has two states like "a" "b", i.e, each one will become different entity,like 2a,2b,3a,3b,1a,
with only exception i.e. 1 will have only one state 1a.
please tel me step wise using formulas, so that i can understand, also any link will be helpfull.
yours sincerly
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