Implicit Differentiation: dy/dx of xe^y-y=x^2-2, Y=...

[john.johnson]

Could someone tell me if have the right answer for this questions?

\(\displaystyle y'\, =\, \dfrac{2x\, -\, e^y}{e^y x \, -\, 1}\)

dy/dx of xe^y-y=x^2-2

Y= (2x-e^y)/(e^yx-1)

Hopefully I typed this correctly...

 

[Ishuda]

Could someone tell me if have the right answer for this questions?

dy/dx of xe^y-y=x^2-2

Y= (2x-e^y)/(e^yx-1)

Hopefully I typed this correctly...

Answer is correct, assuming y' is what is wanted, but I would write it as
Y = y' = (2x - e^y) / (x e^y - 1)
for, hopefully, a little more clarity.

 

[john.johnson]

Answer is correct, assuming y' is what is wanted, but I would write it as
Y = y' = (2x - e^y) / (x e^y - 1)
for, hopefully, a little more clarity.

Thank you Ishuda!
I appreciate it