Equation Conversion

U

urglik

New member
Joined
Jun 3, 2015
Messages
7
howdy everyone,

i was hoping someone could tell me if the following two expressions equal their respective equations in the pictures.

this is for an online spherical resonator calculator i have made.


17.87*((d/(f^2))^(1/3))

equationnoneck.gif


((3*(d^2)*(C^2))/(8*L*(f^2)*(pi^2)))^(1/3)

equationeck.jpg


i do not understand the triple parenthesis in the second expression though i cannot get
it to work without it.


thank you,

urg
 
urglik said:
howdy everyone,

i was hoping someone could tell me if the following two expressions equal their respective equations in the pictures.

this is for an online spherical resonator calculator i have made.


17.87*((d/(f^2))^(1/3))

View attachment 5365


((3*(d^2)*(C^2))/(8*L*(f^2)*(pi^2)))^(1/3)

View attachment 5366


i do not understand the triple parenthesis in the second expression though i cannot get
it to work without it.


thank you,

urg
Click to expand...

You should write the second expression as:


[{3*(d^2)*(C^2)}/{8*L*(f^2)*(pi^2)}]^(1/3)

However, You could also write


[3 * d^2 * C^2 /{8 * L * f^2 * pi^2 }]^(1/3)
 
urglik said:
howdy everyone,

...
((3*(d^2)*(C^2))/(8*L*(f^2)*(pi^2)))^(1/3)

...i do not understand the triple parenthesis in the second expression though i cannot get
it to work without it.


thank you,

urg
Click to expand...

((3*(d^2)*(C^2))/(8*L*(f^2)*(pi^2)))^(1/3)
 
thank you subhotosh khan.

for the online calculator, i like the openess and simplicity of your second suggestion regarding the second equation.

both are elegant.
 
Last edited:
Denis said:
WAY too many brackets; this'll do:
[3*d^2*c^2 / (8*L*f^2*pi^2)]^(1/3)
Click to expand...

Simplicity is in the eye of the beholder! For me the most simple would be:

1/2 * (3/L)^(1/3) *[c*d /(f*pi)]^(2/3)
 
Subhotosh Khan said:
Simplicity is in the eye of the beholder! For me the most simple would be:

1/2 * (3/L)^(1/3) *[c*d /(f*pi)]^(2/3)
Click to expand...

the ability to move this equation around is beyond my pay grade,
though i am totally interested in why you, Subhotosh Khan, feel that your last equation is
a good example of simplicity. i like your quote at the bottom of your posts.

originally, i found an equation in a book in a library many years
ago that was solved for the frequency. wandering around the
physics dept at the univ i found a person to solve it for the diameter.
it appears to be correct, but more testing is needed.
in the time i have spent searching online, i have been unable
to verify the veracity of either equation..
 
balifon

balafon+frame+1+copy.jpg

timbila (with an unseen necked sound hole and a membrane covered trumpet)

5b8d6a15a38361dda3b3829f0f993bbf.jpg
 
i see that subhotosh khan has 120 more posts than you do denis.
don't you think you're being a little cheeky? [2*(lol)]^2
 
You must log in or register to reply here.
Top