Log simplification problem

[Jackjack1123]

Im having trouble working out how to calculate p from the below equation,

12=10*log10(p/5x10^-9)

its basically 12db signal to noise ratio (snr) detected at a reciever and the detected noise power is 5nW but power (p) is needed and i cant quite get my head around how to simplify it down because im not that good with logs!

Thanks in advance

 

[Deleted member 4993]

Im having trouble working out how to calculate p from the below equation,

12=10*log10(p/5x10^-9)

its basically 12db signal to noise ratio (snr) detected at a reciever and the detected noise power is 5nW but power (p) is needed and i cant quite get my head around how to simplify it down because im not that good with logs!

Thanks in advance

\(\displaystyle 12 \ = \ Log_{10}\left [\dfrac{p}{5*10^{-9}}\right ] \)

Use properties of Log functions:

Log_a(b/c) = Log_a(b) - Log_a(c) and

Log_a(b^c) = c * Log_a(b)

What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

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[stapel]

Im having trouble working out how to calculate p from the below equation,

12=10*log10(p/5x10^-9
...and i cant quite get my head around how to simplify it down because im not that good with logs!

To clarify logs, try here.