Methods of partial fraction

[asilvester635]

I used wolfram alpha to check my answer (located in Part 2). What they got is different from mine. I don't know if they simplified their answer which might be the reason why it looks different from my answer. Did I do anything wrong?

 

[Deleted member 4993]

I used wolfram alpha to check my answer (located in Part 2). What they got is different from mine. I don't know if they simplified their answer which might be the reason why it looks different from my answer. Did I do anything wrong?

Try differentiating your answer - and see if you get the original integrand back. If you do - your work is "most probably" correct.

 

[Ishuda]

I used wolfram alpha to check my answer (located in Part 2). What they got is different from mine. I don't know if they simplified their answer which might be the reason why it looks different from my answer. Did I do anything wrong?

A+B-C = \(\displaystyle (-\frac{11}{4})\, +\, (\frac{13}{4})\, -\, (-\frac{2}{4})\, =\, ?\)
and what is supposed to equal?

 

[asilvester635]

It's equal to 1. What are you trying to tell me?

 

[Ishuda]

It's equal to 1. What are you trying to tell me?

A+B-C is the coefficient of x in the resulting partial fraction reintegration. What should the coefficient of x be?