differentiating functions: f(x)=5x^2ln(3x)

Snow2021

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Dec 15, 2014
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Hello all

Im struggling with some differentiating and want to know where to go next

The question i have is

f(x)=5x^2ln(3x) now i know i should be using the product rule so it should be f(x)*g'(x)+g(x)*f'(x)

so that should give me 5x^2*1/3+ln(3x)*10x

but when i have tried putting the same question into something like mathway my numbers dont represent the same and how do i go on to simplify this. Im trying to follow the books but i just can't get it to click in my head so maybe someone explaining it might be of more use

Regards
Snow
 
Hello all

Im struggling with some differentiating and want to know where to go next

The question i have is

f(x)=5x^2ln(3x) now i know i should be using the product rule so it should be f(x)*g'(x)+g(x)*f'(x)

so that should give me 5x^2*1/3+ln(3x)*10x

but when i have tried putting the same question into something like mathway my numbers dont represent the same and how do i go on to simplify this. Im trying to follow the books but i just can't get it to click in my head so maybe someone explaining it might be of more use

Regards
Snow

g(x) = ln(3*x)

g'(x) = 1/(3*x) * 3 = 1/x

h(x)= x^2

h'(x) = 2*x

d/dx [5x^2 * ln (3x)]

=5[x^2 * (1/x) + 2*x * ln(3x)]

= 5[x + 2*x*ln(3x)]
 
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