K KatieK New member Joined Apr 13, 2016 Messages 1 Apr 13, 2016 #1 I can't figure this one out. In rectangle ABDE, AB=12 and BD=16. For rhombus ACDF, find the difference between the are and the perimter. Attachments 20160413_105446.jpg 483.3 KB · Views: 10
I can't figure this one out. In rectangle ABDE, AB=12 and BD=16. For rhombus ACDF, find the difference between the are and the perimter.
I Ishuda Elite Member Joined Jul 30, 2014 Messages 3,342 Apr 13, 2016 #2 KatieK said: I can't figure this one out. In rectangle ABDE, AB=12 and BD=16. For rhombus ACDF, find the difference between the are and the perimter. Click to expand... What are your thoughts? What have you done so far? Please show us your work even if you feel that it is wrong so we may try to help you. You might also read http://www.freemathhelp.com/forum/threads/78006-Read-Before-Posting Hint: Given no more information than that, the question does not have a unique answer.
KatieK said: I can't figure this one out. In rectangle ABDE, AB=12 and BD=16. For rhombus ACDF, find the difference between the are and the perimter. Click to expand... What are your thoughts? What have you done so far? Please show us your work even if you feel that it is wrong so we may try to help you. You might also read http://www.freemathhelp.com/forum/threads/78006-Read-Before-Posting Hint: Given no more information than that, the question does not have a unique answer.