Calculus Average Velocity: particle moving along line according to (t)=-19t^2+133t

[helpmeplz]

[FONT=&quot]I do not know what I am doing wrong? Please someone help me check my math and see where I made the mistake.

The question:

The position of an object moving along a line is given by the function s(t)=-19t^2+133t. [/FONT]

[FONT=&quot]Find the average velocity at the following interval: [1,1+h]

So I got (19+38+19h^2+133+133h-114)/h

simplifies to 76+19h^2+133h/h

I factored the h and got 76+19h+133

I got the final answer as 209+19h.......where did I go wrong?[/FONT]

 

[Deleted member 4993]

I do not know what I am doing wrong? Please someone help me check my math and see where I made the mistake.

The question:

The position of an object moving along a line is given by the function s(t)= -19t^2+133t.

Find the average velocity at the following interval: [1,1+h]

So I got (-19 - 38h - 19h^2 + 133 + 133h -114)/h

simplifies to (76+19h^2+133h)/h .......... incorrect! see above

I factored the h and got 76 (?)+19h+133 ............ How did you get that from the line above?!

I got the final answer as 209+19h.......where did I go wrong?

Correct your arithmetic then continue....