Steven G
Elite Member
- Joined
- Dec 30, 2014
- Messages
- 14,541
I am not seeing this one
From 27 pieces of luggage, an airline luggage handler damages a random
sample of four. The probability that exactly one of the damaged pieces of
luggage is insured is twice the probability that none of the damaged pieces
are insured. Calculate the probability that exactly two of the four damaged
pieces are insured.
I think that the 27 is not needed.
P (exactly 0 Insured) + P ( exactly 1 insured) + P( exactly 2 insured) + ... + P( 4 insured) = 1
so x + 2x + P( exactly 2 insured) + ... + P( 4 insured) =1
I'm not seeing exactly what The probability that exactly one of the damaged pieces ofluggage is insured is twice the probability that none of the damaged pieces
are insured is really saying
From 27 pieces of luggage, an airline luggage handler damages a random
sample of four. The probability that exactly one of the damaged pieces of
luggage is insured is twice the probability that none of the damaged pieces
are insured. Calculate the probability that exactly two of the four damaged
pieces are insured.
I think that the 27 is not needed.
P (exactly 0 Insured) + P ( exactly 1 insured) + P( exactly 2 insured) + ... + P( 4 insured) = 1
so x + 2x + P( exactly 2 insured) + ... + P( 4 insured) =1
I'm not seeing exactly what The probability that exactly one of the damaged pieces ofluggage is insured is twice the probability that none of the damaged pieces
are insured is really saying