MathLearner2016
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- Joined
- Dec 1, 2016
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2 cards are drawn from a 52 card deck. The random variable X represents the number of aces drawn. The random variable distribution:
X = 0 : P(0) = 0.849
X = 1 : P(1) = 0.145
X = 2 : P(2) = 0.005
Is this how you do it?
Probability of the draws:
0 aces out of 2 cards:
C(48,2) * C(4,0) / C(52,2)
1128 / 1328 = 0.849
1 ace out of 2 cards:
C(48,1) * C(4,1) / C(52,2)
48 * 4 / 1328 = 0.145
2 aces out of 2 cards:
C(48,0) * C(4,2) / C(52,2)
6 / 1328 = 0.005
X = 0 : P(0) = 0.849
X = 1 : P(1) = 0.145
X = 2 : P(2) = 0.005
Is this how you do it?
Probability of the draws:
0 aces out of 2 cards:
C(48,2) * C(4,0) / C(52,2)
1128 / 1328 = 0.849
1 ace out of 2 cards:
C(48,1) * C(4,1) / C(52,2)
48 * 4 / 1328 = 0.145
2 aces out of 2 cards:
C(48,0) * C(4,2) / C(52,2)
6 / 1328 = 0.005