I bet the OP meant r6a - 3r96a- 6r24a. It boggles my mind that someone can't tell that what they wrote is unclear.can someone please show me the steps to combining this?
r6a -3r96a -6r24a
Could someone show me the steps to combine this?Er... as you've posted, there's two variables (r and a) and no radicals in the problem, and so it's a matter of combining like terms. Based on your choice of subject line, I'll go out on a limb and assume that "r" is your notation for "radical." Although, that still leaves quite a bit of confusion you'll need to clear up. Is the problem:
\(\displaystyle \sqrt{6}a-3\sqrt{96}a-6\sqrt{24}a\)
or maybe \(\displaystyle \sqrt{6a}-3\sqrt{96a}-6\sqrt{24a}\)
...or something else entirely?
When you reply back, please also include any and all work you've done on this problem, even if you know it's wrong. Thank you.
Could someone show me the steps to combine this?
\(\displaystyle \sqrt{6}a-3\sqrt{96}a-6\sqrt{24}a\)
Shouldn't there be an "a" in that last answer?\(\displaystyle \sqrt{96}=\sqrt{16\cdot 6}=4\sqrt{6}\)
\(\displaystyle \sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}\)
\(\displaystyle 1-12-12=-23\)
\(\displaystyle \begin{align*}\sqrt{6}a-3\sqrt{96}a-6\sqrt{24}a &=\sqrt{6}a-12\sqrt{6}a-12\sqrt{6}a \\&=-23\sqrt{6}\end{align*}\)
Shouldn't there be an "a" in that last answer [due to typo/oversight]?