U Umar New member Joined Jul 14, 2017 Messages 1 Jul 14, 2017 #1 For the equation, find dy/dx evaluated at the given values. y2 = 8x − 71 at x = 9, y = −1 dy/dx =
D Deleted member 4993 Guest Jul 14, 2017 #2 Umar said: For the equation, find dy/dx evaluated at the given values. y2 = 8x − 71 at x = 9, y = −1 dy/dx = Click to expand... What are your thoughts? Please share your work with us ...even if you know it is wrong. If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/announcement.php?f=33
Umar said: For the equation, find dy/dx evaluated at the given values. y2 = 8x − 71 at x = 9, y = −1 dy/dx = Click to expand... What are your thoughts? Please share your work with us ...even if you know it is wrong. If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/announcement.php?f=33
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Jul 14, 2017 #3 Umar said: For the equation, find dy/dx evaluated at the given values. y2 = 8x − 71 at x = 9, y = −1 Click to expand... Where are you stuck in the implicit differentiation? You differentiated y^2 and got... what? You differentiated 8x - 71 and got... what? When you plugged in the given values and solve for dy/dx, you got... what? Please be complete. Thank you!
Umar said: For the equation, find dy/dx evaluated at the given values. y2 = 8x − 71 at x = 9, y = −1 Click to expand... Where are you stuck in the implicit differentiation? You differentiated y^2 and got... what? You differentiated 8x - 71 and got... what? When you plugged in the given values and solve for dy/dx, you got... what? Please be complete. Thank you!